If 10.0 L of ethene gas at STP is completely polymerised to polyethylene, calculate the mass of polyethylene formed. (Molar mass of repeating unit C₂H₄ = 28 g mol∑, assume polymer contains the same number of repeating units as moles of ethene reacted).
Answer
12.5 g
The correct answer is 12.5 g — – Therefore 12.5 g of polyethylene is produced.
Step-by-step solution
- Determine moles of ethene: 10.0 L ÷ 22.4 L mol∑ = 0.4464 mol.
- Each mole of ethene gives one repeating unit in the polymer.
- Total moles of repeating units = 0.4464 mol.
- Mass of polyethylene = 0.4464 mol × 28 g mol∑ = 12.5 g.
- – Therefore 12.5 g of polyethylene is produced.
Common mistake: Using 22.4 L for STP but not converting correctly
Concept tested: Polymerisation mass calculation
Published · How this solution was prepared and checked
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