If two carriers of an autosomal recessive disease (Aa) have four children, how many children are expected to be affected?
Answer
1
The correct answer is 1 — Multiply this probability by the number of children: 4 * 1/4 = 1.
Step-by-step solution
- Probability of an affected child in Aa x Aa cross is 1/4.
- Multiply this probability by the number of children: 4 * 1/4 = 1.
Common mistake: Assuming carriers produce affected children at 1/2 probability
Concept tested: Autosomal recessive inheritance
Published · How this solution was prepared and checked
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