In a 4.00 g sample of the complex ‛[Fe(NH3)6]Cl3”, what is the mass of iron present?
Answer
0.846 g
The correct answer is 0.846 g — Answer: 0.846 g.
Step-by-step solution
- Calculate molar mass of the complex: Fe (55.85) + 6·NH3 (6·17.03) + 3·Cl (3·35.45) = 264.2 g/mol.
- Find the number of moles of complex in 4.00 g: 4.00 g ÷ 264.2 g/mol = 0.01515 mol.
- Multiply by the molar mass of Fe to find mass of Fe: 0.01515 mol × 55.85 g/mol = 0.846 g.
- Answer: 0.846 g.
Common mistake: Using incorrect molar mass for NH3
Concept tested: Mole–mass calculation for coordination complex
Published · How this solution was prepared and checked
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