A monohybrid cross of two heterozygous pea plants (Aa × Aa) is performed. If 2000 seeds are sown, approximately how many will exhibit the dominant phenotype?
Answer
1500
The correct answer is 1500 — Thus, about 1500 seeds will show the dominant phenotype.
Step-by-step solution
- Use Mendelian monohybrid segregation ratio: 3 parts dominant : 1 part recessive.
- Compute the proportion of dominant phenotype: 3/(3+1) = 3/4 = 0.75.
- Multiply by the total number of seeds: 0.75 × 2000 = 1500.
- Round to nearest whole number: 1500.
- Thus, about 1500 seeds will show the dominant phenotype.
Common mistake: Using 1/3 instead of 3/4 for dominant proportion
Concept tested: Monohybrid segregation ratio
Published · How this solution was prepared and checked
← All Principles of Inheritance and Variation questions