For a diploid flowering plant with chromosome number $2n=12$, how many distinct haploid gamete types can be produced solely by independent assortment?

Step-by-step solution

1. The diploid number $2n=12$ gives $n=6$ chromosome pairs.
2. Each pair has two homologues that can segregate independently.
3. Thus each pair offers 2 choices of which homologue enters a gamete.
4. The total number of combinations is $2^6=64$.
5. Therefore 64 distinct haploid gamete types are possible.

Concept tested: Independent assortment

Published 28 September 2026 · How this solution was prepared and checked