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Which of the following products is obtained when cyclohexanone is treated with sodium borohydride (NaBH4) in ethanol?

easy MCQ 1 mark Class 12 · Chemistry · Aldehydes Ketones and Carboxylic Acids
  1. Cyclohexanol
  2. Cyclohexanone (no change)
  3. Cyclohexyl bromide
  4. Cyclohexylamine
Answer
Cyclohexanol

The correct answer is Cyclohexanol — Thus cyclohexanone (a ketone) is reduced to cyclohexanol (a secondary alcohol).

Step-by-step solution

  1. Identify the reagent: NaBH4 is a mild reducing agent that donates hydride ions (H⁻) to carbonyl groups.
  2. Cyclohexanone contains a C=O carbonyl group; NaBH4 will add a hydride to the carbonyl carbon and a proton to the oxygen.
  3. The addition converts the carbonyl (C=O) into a hydroxyl (C–OH) group, giving the corresponding alcohol.
  4. Thus cyclohexanone (a ketone) is reduced to cyclohexanol (a secondary alcohol).
Common mistake: Confusing NaBH4 with a strong reducing agent that can also reduce C–X bonds; it only reduces C=O.

Concept tested: Reduction of carbonyl compounds

Published · How this solution was prepared and checked

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