Explain the mechanism of the Hofmann rearrangement when benzamide is treated with sodium hypochlorite () and sodium hydroxide (). Write the balanced overall chemical equation and name the organic product formed.
Answer
Overall equation: . The organic product is aniline (phenylamine).
Step-by-step solution
- Step 1: Generation of hypochlorite ion – NaOCl dissociates in water to give .
- Step 2: The amide nitrogen attacks the electrophilic forming N‑chloro‑amide ().
- Step 3: In the strongly basic medium, the N‑chloro‑amide loses a proton to give the anionic N‑chloro‑amide ().
- Step 4: A second hydroxide ion abstracts a proton from the carbonyl carbon, producing a tetrahedral intermediate that collapses, expelling chloride ion and forming a nitrene‑like intermediate that rearranges to an isocyanate ().
- Step 5: The isocyanate is rapidly hydrolyzed by water (present from NaOH) to give aniline and carbonic acid. The carbonic acid reacts with excess NaOH to give sodium carbonate ().
- Step 6: Combine all stoichiometric coefficients: one mole of benzamide reacts with one mole of NaOCl and two moles of NaOH to give one mole of aniline, one mole of NaCl, one mole of , and one mole of water.
- Step 7: Write the balanced overall equation: .
- Step 8: Identify the organic product – the amine formed is aniline, also called phenylamine.
Common mistake: Confusing the product with a carboxylic acid; the carbonyl carbon is lost as CO₂ (as carbonate), not retained in the product.
Concept tested: Hofmann rearrangement mechanism
Published · Last updated · How this solution was prepared and checked
← All Amines questions