A 4.00 g sample of triglyceride ${\text{C}}_{55}{\text{H}}_{104}{\text{O}}_6$ is completely saponified with excess NaOH. The reaction consumes 0.300 mol of NaOH. Calculate the saponification value (mg KOH g⁻¹).

Step-by-step solution

1. Determine moles of NaOH per gram of fat: $\frac{0.300\text{ mol}}{4.00\text{ g}}=0.075{\text{ mol g}}^{-1}$.
2. Convert moles of NaOH to mg KOH (1 mol NaOH ≈ 1 mol KOH) and multiply by 1000: $0.075\times 1000=75$ mg KOH per g fat.
3. Present the saponification value: $75{\text{ mg KOH g}}^{-1}$.

Concept tested: Calculating saponification value of a fat

Published 9 September 2026 · How this solution was prepared and checked