Determine the oxidation state of the metal atom in the complex ion [Ni(en)[3]^2+, where [en] is ethylenediamine (en is a neutral ligand).
Answer
Ni(II)
The correct answer is Ni(II) — Let the oxidation state of Ni be x. Then x + 3(0) = +2. Thus x = +2. Therefore the metal is in the +2 oxidation state.
Step-by-step solution
- Assign oxidation numbers to all atoms: en is neutral, so the complex carries the charge of the metal ion.
- The overall charge of the complex is +2.
- Let the oxidation state of Ni be x. Then x + 3(0) = +2. Thus x = +2. Therefore the metal is in the +2 oxidation state.
Common mistake: Assuming the complex has a negative charge because of the ligand
Concept tested: Oxidation state calculation in coordination complexes
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