p‑Chloronitrobenzene (, chlorine para to the nitro group) is treated with excess NaNH₂ in liquid ammonia at 298 K.
Answer
Major product: m‑Aminonitrobenzene (3‑amino‑4‑nitrobenzene)
The correct answer is Major product: m‑Aminonitrobenzene (3‑amino‑4‑nitrobenzene) — The strongly basic medium (NaNH₂) is essential for both deprotonation (step 1) and nucleophilic attack (step 3).
Step-by-step solution
- The nitro group is a strong –I and –M deactivator; it makes the ring less susceptible to the direct addition‑elimination (SNAr) pathway, which requires an electron‑withdrawing group ortho or para to the leaving halogen.
- Because the nitro group is para to chlorine, the ortho positions (2 and 6) are activated for deprotonation by the very strong base NaNH₂, favouring benzyne formation.
- Thus the benzyne mechanism is the preferred pathway.
- (b) Attack of NaNH₂ on the benzyne intermediate mainly occurs at the carbon meta to the nitro group, giving 3‑amino‑4‑nitrobenzene as the major product.
- (c) Mechanistic steps:
- 1. NaNH₂ abstracts a proton from the carbon ortho to chlorine (position 2), generating a carbanion.
- 2. The carbanion expels the chloride ion, producing a highly reactive benzyne (a triple bond between C1 and C2).
- 3. The amide ion (NH₂⁻) adds to the benzyne at either carbon of the triple bond; addition at C2 (the carbon meta to the nitro group) is favoured because the nitro group withdraws electron density from C1, making C2 more electrophilic.
- 4. The resulting anionic intermediate is protonated by solvent (NH₃) to give the aromatic amine product, 3‑amino‑4‑nitrobenzene.
- The strongly basic medium (NaNH₂) is essential for both deprotonation (step 1) and nucleophilic attack (step 3).
Common mistake: Assuming the nitro group will always direct a direct SNAr substitution
Concept tested: Benzyne mechanism in nucleophilic aromatic substitution
Published · How this solution was prepared and checked
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