How many grams of NaOH are required to prepare 0.500 L of 3.00 M NaOH solution?

Step-by-step solution

1. Step 1: Calculate moles of NaOH needed using $n=M\times V$.
2. Step 2: Substitute $M=3.00{\text{mol L}}^{-1}$ and $V=0.500\text{L}$ to get $n=1.5\text{mol}$.
3. Step 3: Convert moles to grams using $m=n\times M_{\text{NaOH}}$ where $M_{\text{NaOH}}=40.0{\text{g mol}}^{-1}$.
4. Step 4: Compute $m=1.5\times 40.0=60.0\text{g}$.

Concept tested: Molarity of a solution

Published 6 September 2026 · Last updated 16 September 2026 · How this solution was prepared and checked