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For what value of (k) is the determinant of zero?

medium 2 marks Class 12 · Mathematics · Determinants
Answer
3

The correct answer is 3 — Solve for k: 8k = 24 → k = 3.

Step-by-step solution

  1. Write det = k×8 − 4×6.
  2. Simplify: det = 8k − 24.
  3. Set det = 0: 8k − 24 = 0.
  4. Solve for k: 8k = 24 → k = 3.
Common mistake: Incorrectly setting 6k − 4×8 = 0.

Concept tested: Determinant zero condition

Published · How this solution was prepared and checked

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