Solve the non‑homogeneous linear differential equation with the initial conditions and .
Answer
The correct answer is — Combine the and : after simplification (note: algebraic simplification yields the same expression).
Step-by-step solution
- Write the associated homogeneous equation: .
- Form the characteristic equation: .
- Factor to get ; thus .
- Hence the complementary (homogeneous) solution: .
- For the particular solution, try because the RHS is and already appears in the complementary solution, multiply by : assume .
- Compute derivatives: , .
- Substitute into the differential equation: .
- Simplify: which reduces to .
- Thus giving .
- Therefore .
- The general solution: .
- Apply the initial condition : .
- Differentiate the general solution: .
- Apply : giving .
- Solve the system and . Subtract the first from the second: . Then .
- Substitute back: .
- Combine the and : after simplification (note: algebraic simplification yields the same expression).
Common mistake: Choosing a particular solution of the form without multiplying by when is a root of the characteristic equation
Concept tested: Second‑order linear ODE with constant coeffs
Published · How this solution was prepared and checked
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