Lesson eLearning

Solve the non‑homogeneous linear differential equation with the initial conditions and .

hard 5 marks Class 12 · Mathematics · Differential Equations
Answer

The correct answer is — Combine the and : after simplification (note: algebraic simplification yields the same expression).

Step-by-step solution

  1. Write the associated homogeneous equation: .
  2. Form the characteristic equation: .
  3. Factor to get ; thus .
  4. Hence the complementary (homogeneous) solution: .
  5. For the particular solution, try because the RHS is and already appears in the complementary solution, multiply by : assume .
  6. Compute derivatives: , .
  7. Substitute into the differential equation: .
  8. Simplify: which reduces to .
  9. Thus giving .
  10. Therefore .
  11. The general solution: .
  12. Apply the initial condition : .
  13. Differentiate the general solution: .
  14. Apply : giving .
  15. Solve the system and . Subtract the first from the second: . Then .
  16. Substitute back: .
  17. Combine the and : after simplification (note: algebraic simplification yields the same expression).
Common mistake: Choosing a particular solution of the form without multiplying by when is a root of the characteristic equation

Concept tested: Second‑order linear ODE with constant coeffs

Published · How this solution was prepared and checked

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