For the matrix and the vector , determine the rank of and state whether the linear system is consistent. If consistent, give the general solution.
Answer
Infinitely many solutions;
The correct answer is Infinitely many solutions; — Solve by parameterizing: Let . From first row: . Express and as multiples of . The simplest representation is .
Step-by-step solution
- Check if rows are multiples: row2=2×row1, row3=3×row1. So rank of is 1.
- Form augmented matrix .\nSince is also a multiple of row1 (), the augmented matrix has the same rank 1.
- Ranks of coefficient and augmented matrices are equal; therefore system is consistent.
- Because , there are infinitely many solutions.
- Solve by parameterizing: Let . From first row: . Express and as multiples of . The simplest representation is .
Common mistake: Assuming only zero solution because coefficient matrix has rank 1
Concept tested: Rank and consistency of a linear system
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