Determine whether the function is one‑to‑one on the set of real numbers. Justify your answer.
Answer
No.
The correct answer is No. — Conclude that is not one‑to‑one on .
Step-by-step solution
- Express as to identify it as a perfect square.
- Compute and ; two distinct inputs give the same output.
- Since , the function is not injective.
- Conclude that is not one‑to‑one on .
Common mistake: Assuming vertex implies non‑injectivity without checking values
Concept tested: Injectivity of quadratic function
Published · How this solution was prepared and checked
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