How many distinct equivalence relations can be defined on the set ?
Answer
5
The correct answer is 5 — There are 5 partitions; therefore there are 5 distinct equivalence relations on .
Step-by-step solution
- An equivalence relation corresponds to a partition of the underlying set.
- List all possible partitions of a 3‑element set:
- 1) \{\{a\},\{b\},\{c\}\} (three singletons).
- 2) \{\{a,b\},\{c\}\}.
- 3) \{\{a,c\},\{b\}\}.
- 4) \{\{b,c\},\{a\}\}.
- 5) \{\{a,b,c\}\} (the whole set as one block).
- Each partition determines exactly one equivalence relation, so the number of equivalence relations equals the number of partitions.
- There are 5 partitions; therefore there are 5 distinct equivalence relations on .
Common mistake: Counting ordered pairs or forgetting that the partition \{\{a\},\{b\},\{c\}\} also yields a valid equivalence relation.
Concept tested: Counting equivalence relations via partitions
Published · How this solution was prepared and checked
Related questions
- 1 Consider the relation R from set A={1,2,3,4} to set B={2,4,6,8} given by R={(1,2),(2,4),(3,6),(4,8)}. Which of the following statements is correct?
- 2 Let f:R→R be defined by f(x)= x^2, x≤ 1 2x+1, x>1 Find the domain and the range of f.
- 3 Let f:R→R be defined by f(x)=3x-5 and g:R→R by g(x)=(x+2)/3. i Prove that both f and g are one‑one and onto. ii Find the compositions (f° g)(x) and (g° f)(x). iii Determine the inverse function f^-1 and verify that f^-1(f(x))=x for all x∈R.
- 4 Find all real values of k for which the system x+y+z=2, 2x+3y+kz=5, 3x+4y+(k+1)z=7 has infinitely many solutions.
- 5 For the system x+2y-z=3, 2x+4y-2z=6, 3x+6y-5z=2, find the rank of the coefficient matrix and the augmented matrix and state whether the system is consistent. If it is consistent, give the solution.
- 6 A firm produces product A and product B. 1 unit of A requires 1 unit of resource 1 and 3 units of resource 2. 1 unit of B requires 4 units of resource 1 and 2 units of resource 2. Daily availability: resource 1 = 20 units, resource 2 = 30 units. Profit per unit: A = ₹50, B = ₹60. Using the simplex method, find the maximum profit.