A 1.5 m nichrome wire has a cross‑sectional area of 0.6 mm² and a resistivity of $1.10\times 10^{-6}\Omega \text{m}$ at 20°C. What is its resistance?

Step-by-step solution

1. Convert area to m²: $0.6{\text{ mm}}^2=0.6\times 10^{-6}{\text{ m}}^2$.
2. Use $R=\rho L/A$: $R=(1.10\times 10^{-6}\times 1.5)/(0.6\times 10^{-6})$.
3. Compute numerator: $1.10\times 10^{-6}\times 1.5=1.65\times 10^{-6}$.
4. Divide by denominator: $1.65\times 10^{-6}/0.6\times 10^{-6}=2.75$.
5. Hence $R=2.75\Omega$.

Concept tested: Resistance of a wire from resistivity

Published 16 October 2026 · How this solution was prepared and checked