A nichrome wire has length $1.8,\text{m}$, cross‑sectional area $0.6,{\text{mm}}^2$ and resistivity $1.10\times 10^{-6},\Omega ,\text{m}$ at $20^{\circ }\text{C}$. Calculate its resistance.

Step-by-step solution

1. Convert the cross‑sectional area to square metres: $0.6,{\text{mm}}^2=0.6\times 10^{-6},{\text{m}}^2$.
2. Apply the resistance formula $R=\rho L/A$.
3. Substitute the values: $R=(1.10\times 10^{-6},\Omega ,\text{m})(1.8,\text{m})/(0.6\times 10^{-6},{\text{m}}^2)$.
4. Simplify: $R=3.3,Omega$.

Concept tested: Resistivity and resistance calculation

Published 10 September 2026 · Last updated 16 September 2026 · How this solution was prepared and checked