A spherical surface of radius $0.10\text{m}$ is placed in a uniform electric field of magnitude $3.0\times 10^4\text{N/C}$ directed along the $+x$ direction. What is the net electric flux through the spherical surface?

Step-by-step solution

1. Recall Gauss's law: the net flux through a closed surface equals $\frac{Q_{\text{enc}}}{{\epsilon }_0}$.
2. Identify the charge enclosed by the sphere. Since only a uniform external field is present and no charge is inside, $Q_{\text{enc}}=0$.
3. Apply Gauss's law: $\Phi =\frac{0}{{\epsilon }_0}=0$.
4. Therefore, the net electric flux through the sphere is zero, regardless of the field magnitude.

Concept tested: Gauss's law – net flux

Published 10 September 2026 · How this solution was prepared and checked