A straight conducting rod of length 0.60 m moves with a constant speed of 4.0 m s\textsuperscript{-1} perpendicular to a uniform magnetic field of magnitude 0.30 T directed into the page. Find the magnitude of the induced emf across the ends of the rod.

Step-by-step solution

1. Identify the motional emf formula: $E=B,v,L$, where $v$ is the velocity perpendicular to the field and $L$ is the rod length.
2. Substitute the given values: $E=0.30,\text{T}\times 4.0,{\text{m s}}^{-1}\times 0.60,\text{m}$.
3. Compute the product: $0.30\times 4.0\times 0.60=0.72$.
4. State the result: the induced emf is $0.72\text{ V}$.

Concept tested: Faraday’s law for motional emf

Published 18 September 2026 · How this solution was prepared and checked