A magnetic dipole moment μ=3.0;A,$m^2$ is placed in a uniform magnetic field of magnitude 0.4,T. If the dipole moment is perpendicular to the field, what is the torque experienced by the dipole?

Step-by-step solution

1. Identify the torque formula: $\tau =\mu Bsin\theta$.
2. Substitute the given values: $\mu =3.0;A,m^2$, $B=0.4;T$, $\theta =90^{\circ }$.
3. Compute $sin90^{circ}=1$.
4. Calculate $\tau =3.0\times 0.4\times 1=1.2;Ncdotm$.
5. Conclude that the torque magnitude is 1.2 N·m.

Concept tested: torque on a magnetic dipole

Published 15 September 2026 · How this solution was prepared and checked