A 2.0 × 10⁶ m s⁻¹ moving electron enters a uniform magnetic field of 0.5 T perpendicular to its velocity. What is the magnitude of the magnetic force on the electron?

Step-by-step solution

1. The magnitude of magnetic force on a moving charge is given by $F=q,v,B$.
2. The electron’s charge magnitude is $|q|=1.60\times 10^{-19},C$.
3. Substitute the values: $F=(1.60\times 10^{-19},C)(2.0\times 10^6,m/s)(0.5,T)$.
4. Calculate: $F=1.60\times 10^{-19}\times 1.0\times 10^6=1.60\times 10^{-13},N$.
5. Thus the force magnitude is $1.60\times 10^{-13},N$.

Concept tested: Magnetic force on a moving charge

Published 18 September 2026 · How this solution was prepared and checked