A straight conductor of length $0.25,\text{m}$ carries a current of $4,\text{A}$ in a uniform magnetic field of magnitude $0.5,\text{T}$ perpendicular to the conductor. Find the magnitude of the magnetic force on the conductor.

Step-by-step solution

1. Identify the formula for magnetic force on a straight conductor: $F=ILB$.
2. Substitute $I=4,\text{A}$, $L=0.25,\text{m}$ and $B=0.5,\text{T}$.
3. Calculate $IL=4\times 0.25=1$.
4. Multiply by $B$: $1\times 0.5=0.5,\text{N}$.
5. State the magnitude of the force as $0.5,\text{N}$.

Concept tested: Lorentz force on straight conductor

Published 15 September 2026 · Last updated 16 September 2026 · How this solution was prepared and checked