A jug can hold 3 liters and a mug can hold 1 liter. A bottle holds 14 liters. If the number of jugs used is twice the number of mugs, how many jugs and mugs are required to fill the bottle?

Step-by-step solution

1. Let $m$ be the number of mugs and $j$ the number of jugs.
2. Use the given proportion: $j=2m$.
3. Set up the volume equation: $3j+1m=14$.
4. Substitute $j$ in terms of $m$: $3(2m)+m=14$.
5. Simplify: $6m+m=14;Rightarrow;7m=14$.
6. Solve for $m$: $m=2$.
7. Find $j$: $j=2m=4$.
8. Thus 4 jugs and 2 mugs are needed.

Concept tested: Proportional allocation of containers

Published 1 October 2026 · How this solution was prepared and checked