A train travels 300 km from City A to City B in 4 hours 30 minutes. It stops for 15 minutes and then travels 200 km to City C at a constant speed. If the total journey time including the stop is 6 hours, find the speed during the second leg.

Step-by-step solution

1. Convert all times to hours: first leg 4\,h 30\,min = 4.5\,h; stop = 15\,min = 0.25\,h; total time = 6\,h.
2. Compute time for second leg: $t_2=6-4.5-0.25=1.25\text{ h}$.
3. The distance of the second leg is 200 km.
4. Speed for second leg: $v=\frac{200\text{ km}}{1.25\text{ h}}=160\text{ km/h}$.

Concept tested: Time‑speed‑distance relation

Published 13 October 2026 · How this solution was prepared and checked