A puddle has an area of 0.02 m² and evaporates 2.5 mm of water in 12 hours. What is the mass of water evaporated in kilograms?
Answer
0.05 kg
The correct answer is 0.05 kg — Use the density of water (1000 kg/m³) to find mass: 0.00005 m³ × 1000 kg/m³ = 0.05 kg.
Step-by-step solution
- Convert the evaporation thickness to metres: 2.5 mm = 0.0025 m.
- Calculate the volume evaporated: 0.02 m² × 0.0025 m = 0.00005 m³.
- Use the density of water (1000 kg/m³) to find mass: 0.00005 m³ × 1000 kg/m³ = 0.05 kg.
Common mistake: Forgetting to multiply by density or mis‑converting units
Concept tested: Mass of evaporated water calculation
Published · How this solution was prepared and checked
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