A fisherman has 3 buckets. He distributes 98 fish equally among the 3 buckets. How many fish will be in each bucket and how many fish remain?
Answer
32 fish in each bucket, 2 fish remain
The correct answer is 32 fish in each bucket, 2 fish remain — Thus, each bucket gets 32 fish and 2 fish are left over.
Step-by-step solution
- Divide the total fish by the number of buckets: 98 ÷ 3.
- The integer part of the division is the number of fish per bucket.
- 98 ÷ 3 = 32 with a remainder of 2.
- Thus, each bucket gets 32 fish and 2 fish are left over.
Common mistake: Misinterpreting division as exact split
Concept tested: Integer division with remainder
Published · How this solution was prepared and checked
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