If the Earth's circumference at the equator is 40,075 km, what is the speed of a point on the equator in km/h, given that Earth rotates once every 24 hours?

Step-by-step solution

1. Take the equatorial circumference $C=40,075\text{ km}$.
2. The rotation period is $t=24\text{ h}$.
3. Calculate linear speed: $v=\frac{C}{t}=\frac{40,075}{24}\approx 1,669.8\text{ km/h}$.
4. Round to $1,670\text{ km/h}$.

Concept tested: Linear speed from angular motion

Published 7 October 2026 · How this solution was prepared and checked