A student has $\frac{3}{4}$ of a chocolate bar left. He eats $\frac{1}{6}$ of the remaining chocolate and then eats $\frac{1}{5}$ of the chocolate left after that. How much chocolate is left in the end?

Step-by-step solution

1. Initially the student has $\frac{3}{4}$ of a bar.
2. He eats $\frac{1}{6}$ of that: $\frac{1}{6}\times \frac{3}{4}=\frac{3}{24}=\frac{1}{8}$.
3. Chocolate left after first part: $\frac{3}{4}-\frac{1}{8}=\frac{5}{8}$.
4. He then eats $\frac{1}{5}$ of the remaining $\frac{5}{8}$: $\frac{1}{5}\times \frac{5}{8}=\frac{5}{40}=\frac{1}{8}$.
5. Chocolate left after second part: $\frac{5}{8}-\frac{1}{8}=\frac{4}{8}=\frac{1}{2}$.

Concept tested: Subtracting fractions after multiplication

Published 1 October 2026 · How this solution was prepared and checked