Evaluate the expression $(2^3\times 3^2)-(4^1\times 5^0)+(6^1÷2^1)$ and give its numerical value.

Step-by-step solution

1. Compute $2^3$ which equals $8$.
2. Compute $3^2$ which equals $9$.
3. Multiply: $8\times 9=72$.
4. Compute $4^1$ which equals $4$.
5. Compute $5^0$ which equals $1$.
6. Multiply: $4\times 1=4$.
7. Compute $6^1$ which equals $6$.
8. Compute $2^1$ which equals $2$.
9. Divide: $6div2=3$.
10. Apply order of operations: $72-4+3=71$.

Concept tested: Order of operations

Published 16 October 2026 · How this solution was prepared and checked