Solve for $x$ in $\frac{-7}{8}x+\frac{1}{3}=-\frac{5}{12}$.

Step-by-step solution

1. Move $\frac{1}{3}$ to the right side: $\frac{-7}{8}x=-\frac{5}{12}-\frac{1}{3}$.
2. Convert $\frac{1}{3}$ to twelfths: $\frac{1}{3}=\frac{4}{12}$.
3. Add the fractions: $-\frac{5}{12}-\frac{4}{12}=-\frac{9}{12}=-\frac{3}{4}$.
4. Divide both sides by $-\frac{7}{8}$ by multiplying with its reciprocal: $x=\frac{-3/4}{-7/8}=\frac{-3}{4}\times \frac{8}{-7}$.
5. Simplify: $\frac{-24}{-28}=\frac{24}{28}=\frac{6}{7}$.

Concept tested: Solving linear equations with fractions

Published 10 October 2026 · How this solution was prepared and checked