A student prepares 200 mL of a 0.05 M solution of copper(II) sulfate by dissolving solid $\mathrm{CuS}{\mathrm{O}}_4$ in water. How many grams of $\mathrm{CuS}{\mathrm{O}}_4$ are required?

Step-by-step solution

1. Convert the volume to litres: $200,\mathrm{mL}=0.200,\mathrm{L}$
2. Calculate moles of $\mathrm{CuS}{\mathrm{O}}_4$: $0.05,\mathrm{M}\times 0.200,\mathrm{L}=0.01,\mathrm{mol}$
3. Find the molar mass of $\mathrm{CuS}{\mathrm{O}}_4$: $63.55+32.07+4\times 16.00=159.62,g/mol$
4. Calculate mass: $0.01,\mathrm{mol}\times 159.62,g/mol=1.5962,\mathrm{g}$
5. Round to two significant figures (as per given data) to obtain $1.60,\mathrm{g}$.

Concept tested: Preparation of solutions

Published 4 October 2026 · How this solution was prepared and checked