Which volume of 0.05 M NaOH is required to completely neutralise 30 mL of 0.1 M HCl?

easy MCQ 2 marks Class 7 · Science · Acids, Bases and Salts

Answer

60 mL

The correct answer is 60 mL — Determine the volume of 0.05 M NaOH: $\frac{0.003 mol}{0.05 M} = 0.060 L = 60 mL$ .

Step-by-step solution

Compute the moles of HCl: $0.1 M \times 0.030 L = 0.003 mol$ .
Use the 1:1 stoichiometry of the neutralisation reaction: $0.003 mol$ of NaOH are required.
Determine the volume of 0.05 M NaOH: $\frac{0.003 mol}{0.05 M} = 0.060 L = 60 mL$ .

Common mistake: Using a 1:2 ratio instead of 1:1 or mis‑converting litres to millilitres

Concept tested: Neutralisation stoichiometry