A bag contains 4 red, 4 green, and 2 blue balls. Two balls are drawn consecutively without replacement. What is the probability that both balls drawn are red?

Step-by-step solution

1. Probability first ball is red: $\frac{4}{10}=0.4$.
2. After drawing a red, 3 red remain out of 9 balls: $\frac{3}{9}=\frac{1}{3}$.
3. Multiply the probabilities: $0.4\times \frac{1}{3}=\frac{2}{15}\approx 0.1333$.
4. Thus the probability that both balls are red is $\frac{2}{15}$.

Concept tested: Probability of consecutive draws without replacement

Published 7 October 2026 · How this solution was prepared and checked