If the average volume of a single cell is $1.5\times 10^{-12},L$, how many such cells are present in $1,mL$ of a cell suspension?

Step-by-step solution

1. Convert $1,mL$ to liters: $1,mL=1\times 10^{-3},L$.
2. Divide total volume by volume of one cell: $\frac{1\times 10^{-3}}{1.5\times 10^{-12}}=6.6667\times 10^8$.
3. Rounded to one significant figure: $6.7\times 10^8$ cells.

Concept tested: Cell volume and quantity

Published 4 October 2026 · How this solution was prepared and checked