In an open–open pipe of length $0.8,\text{m}$, the fundamental (first harmonic) is produced. If the speed of sound is $340,\text{m/s}$, what is the frequency of this first harmonic?

Step-by-step solution

1. 1. For an open–open pipe, the fundamental wavelength satisfies $L=\frac{\lambda }{2}$, so $\lambda =2L=2\times 0.8=1.6,\text{m}$.
2. 2. Frequency is given by $f=\frac{v}{\lambda }=\frac{340}{1.6},\text{Hz}$.
3. 3. Compute $340÷1.6\approx 212.5,\text{Hz}$.

Concept tested: Standing waves in open–open tube

Published 10 October 2026 · How this solution was prepared and checked