A wooden bar of length 2 m is fixed at one end and free at the other end. Its fundamental frequency of vibration is 200 Hz. Calculate the speed of vibration waves in the bar.

Step-by-step solution

1. For a bar fixed at one end and free at the other, the fundamental frequency is $f=\frac{v}{4L}$ where $v$ is wave speed and $L$ is length.
2. Rearrange to find $v$: $v=4Lf$.
3. Substitute $L=2\text{ m}$ and $f=200\text{ Hz}$: $v=4\times 2\times 200=1600\text{ m/s}$.
4. Thus the wave speed in the bar is $1600\text{ m/s}$.

Concept tested: wave speed from resonator frequency

Published 4 October 2026 · How this solution was prepared and checked