A force of 50 N acts horizontally on a block. The block slides 4 m in the direction of the force. What is the work done by the force?

Step-by-step solution

1. Identify the magnitude of the force $F=50$ N.
2. Identify the displacement $d=4$ m and note that the force is in the direction of displacement, so $\theta =0^{\circ }$ and $cos\theta =1$.
3. Use the formula for work $W=Fdcos\theta$.
4. Multiply to obtain $W=50\times 4\times 1=200$ J.
5. The work done by the force is 200 J.

Concept tested: Work done by a constant force

Published 7 October 2026 · How this solution was prepared and checked