A state legislative assembly has 200 seats. A regional party wins 45 seats, a national party wins 80 seats, and the remaining seats are won by independent candidates. What percentage of seats did independents win? (Give answer to one decimal place.)
Answer
37.5\%
The correct answer is 37.5\% — Round to one decimal place (already 37.5) and add the percent sign.
Step-by-step solution
- Calculate total seats won by parties: 45 (regional) + 80 (national) = 125 seats.
- Find seats won by independents: 200 total – 125 = 75 seats.
- Compute percentage: (75 / 200) × 100 = 37.5.
- Round to one decimal place (already 37.5) and add the percent sign.
Common mistake: Subtracting only the regional party seats from total and forgetting the national party seats, leading to an inflated percentage.
Concept tested: Seat distribution and percentage calculation
Published · How this solution was prepared and checked
Related questions
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