A diploid plant has chromosome number $2n=14$ ($n=7$). During meiosis each chromosome pair can assort independently and each pair can produce two recombinant chromatids due to crossing over. Assuming independent assortment and recombination, how many distinct haploid gamete combinations are theoretically possible?

Step-by-step solution

1. For each chromosome pair, crossing over can generate 4 different chromatids (2 non‑recombinant + 2 recombinant).
2. Hence each pair offers 4 choices for the chromatid that will enter a gamete.
3. With 7 independent pairs, the total combinations are $4^7$.
4. Compute $4^7=16384$.
5. Thus, 16384 distinct haploid gamete combinations are possible.

Concept tested: Gamete diversity by recombination

Published 24 September 2026 · How this solution was prepared and checked