A diploid plant has chromosome number $2n=18$ ($n=9$). Each chromosome pair can assort independently and for each pair, crossing over can produce four different recombinant chromatids. How many distinct haploid gamete combinations are theoretically possible?

Step-by-step solution

1. Each chromosome pair offers 4 choices for the chromatid entering a gamete due to crossing over.
2. With 9 independent pairs, total combinations are $4^9$.
3. Compute $4^9=(2^2{)}^9=2^{18}=262144$.
4. Hence, 262144 distinct haploid gamete combinations are possible.

Concept tested: Gamete combinatorial possibilities

Published 24 September 2026 · How this solution was prepared and checked